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Let $z$, $w$ be complex numbers such that $\bar{z}+i \bar{w}=0$ and $\arg z w=\pi$. Then arg $z$ equals
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Verified Answer
The correct answer is:
$\frac{3 \pi}{4}$
$\frac{3 \pi}{4}$
Here $\omega=\frac{z}{i} \Rightarrow \arg \left(z \cdot \frac{z}{i}\right)=\pi \Rightarrow 2 \arg (z)-\arg (i)=\pi \Rightarrow \arg (z)=\frac{3 \pi}{4}$.
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