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Lifetimes of the molecules in the excited states are often measured by using pulsed radiation source of duration nearly in the nano second range. If the radiation source has the duration of \(2 \mathrm{~ns}\) and the number of photons emitted during the pulse source is \(2.5 \times 10^{15}\), calculate the energy of the source.
ChemistryStructure of Atom
Solution:
2938 Upvotes Verified Answer
Frequency \(=\frac{1}{2 \times 10^{-9} \mathrm{~s}}=0.5 \times 10^9 \mathrm{~s}^{-1}\) Energy \(=\mathrm{N} h v\)
\(\begin{aligned}
&=\left(2.5 \times 10^{15}\right)\left(6.626 \times 10^{-34} \mathrm{Js}\right)\left(0.5 \times 10^9 \mathrm{~s}^{-1}\right) \\
&=8.28 \times 10^{-10} \mathrm{~J}
\end{aligned}\)

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