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Light enters an isosceles right triangular prism at normal incidence through face $\mathrm{AB}$ and undergoes total internal reflection at face $\mathrm{BC}$ as shown below.
The minimum value of the refractive index of the prism is close to
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The minimum value of the refractive index of the prism is close to
Solution:
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Verified Answer
The correct answer is:
$1.42$
$\mathrm{i}=45^{\circ} \geq \mathrm{C}$
For minimum refractive index $C=45^{\circ}$
$\begin{array}{l}
\mu \sin 45^{\circ}=1 \\
\mu=2=1.42
\end{array}$
For minimum refractive index $C=45^{\circ}$
$\begin{array}{l}
\mu \sin 45^{\circ}=1 \\
\mu=2=1.42
\end{array}$
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