Light enters from air into a given medium at an angle of 45 ° with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of 15 ° from its original direction. The refractive index of the medium is :

Question

Light enters from air into a given medium at an angle of 45 ° with interface of the air-medium surface. After refraction, the light ray is deviated through an angle of 15 ° from its original direction. The refractive index of the medium is :, 1 . 732, 1 . 333, 1 . 414, 2 . 732

MARKS App · Accepted Answer

Given here, i = 45 ° Deviation in light ray, D = i - r , here, r is refracted ray. ⇒ 15 ° = 45 - r ⇒ r = 30 ° Using Snell's law, n 1 sin i = n 2 sin r ⇒ 1 sin 45 ° = μ sin 30 ° ⇒ 1 2 = μ 1 2 Thus, the refractive index of the medium is μ = 2 = 1 . 414

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