Light of wavelength 500 nm is incident on a metal with work function 2 . 28 eV . The de Broglie wavelength of the emitted electron is:

Question

Light of wavelength 500 nm is incident on a metal with work function 2 . 28 eV . The de Broglie wavelength of the emitted electron is:, 2.8 × 10 - 9 m, ≥ 2.8 × 10 - 9 m, ≤ 2.8 × 10 - 12 m, 2.8 × 10 - 10 m

MARKS App · Accepted Answer

K E m a x = h c λ - Ψ ⇒ K E m a x = 1240 500 - 2.28 ⇒ K E m a x = 2.48 - 2.28 = 0.2 e V λ m i n = h 2 m KE max = 20 3 × 10 - 34 2 × 9 × 10 - 31 × 0.2 × 1.6 × 10 - 19 λ m i n = 25 9 × 10 - 9 = 2.80 × 10 - 9 m So, λ ≥ 2.8 × 10 - 9 m .

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