Light of wavelength λ = 5000 Å falls normally on a narrow slit. A screen placed at a distance of 1 m from the slit and perpendicular to the direction of light. First minima of the diffraction pattern is situated at 5 m m from the centre of central maximum. The width of the slit is

Question

Light of wavelength λ = 5000 Å falls normally on a narrow slit. A screen placed at a distance of 1 m from the slit and perpendicular to the direction of light. First minima of the diffraction pattern is situated at 5 m m from the centre of central maximum. The width of the slit is, 0.1 m m, 1.0 m m, 0.5 m m, 0.2 m m

MARKS App · Accepted Answer

Position of n t h minima x n = n λ D d 5 × 1 0 - 3 = 1 × 5000 × 1 0 - 10 × 1 d d = 1 0 - 4 m = 0.1 m m .

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