Light of wavelength 550 nm falls normally on a slit of width 22.0 × 10 - 5 cm . The angular position of the second minima from the central maximum will be (in radians):

Question

Light of wavelength 550 nm falls normally on a slit of width 22.0 × 10 - 5 cm . The angular position of the second minima from the central maximum will be (in radians):, π 4, π 8, π 12, π 6

MARKS App · Accepted Answer

a sin θ = 2 λ , 2 n d dark ⇒ sin θ = 2 λ a = 2 × 550 × 10 − 9 22 × 10 − 7 ⇒ θ ≃ π 6 rad

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