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Question: Answered & Verified by Expert
\(\lim _{h \rightarrow 0}\left(\frac{1}{h \sqrt[3]{8+h}}-\frac{1}{2 h}\right)\) equals to
MathematicsLimitsVITEEEVITEEE 2023
Options:
  • A \(-\frac{1}{8}\)
  • B \(\frac{1}{8}\)
  • C \(\frac{1}{48}\)
  • D \(-\frac{1}{48}\)
Solution:
1231 Upvotes Verified Answer
The correct answer is: \(-\frac{1}{48}\)
\(\lim _{h \rightarrow 0} \frac{2-\sqrt[3]{8+h}}{2 h \cdot \sqrt[3]{8+h}}\)
\(\lim _{h \rightarrow 0} \frac{8-(8+h)}{2 h \cdot \sqrt[3]{8+h}\left\{8^{2 / 3}+8^{1 / 3} \cdot (8+h)^{1 / 3}+(8+h)^{2 / 3}\right\}}\)
\(=-\frac{1}{48}\)

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