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Question: Answered & Verified by Expert
$\lim _{n \rightarrow \infty} \sum_{r=1}^n \frac{1}{n} e^{\frac{-}{n}}$ is
MathematicsLimitsJEE MainJEE Main 2004
Options:
  • A
    e
  • B
    $e-1$
  • C
    $1-e$
  • D
    $e+1$
Solution:
2284 Upvotes Verified Answer
The correct answer is:
$e-1$
$\lim _{n \rightarrow \infty} \sum_{r=1}^n \frac{1}{n} e^{\frac{r}{n}}=\int_0^1 e^x d x=(e-1)$

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