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Question: Answered & Verified by Expert
limx01-cos2xxtan2x+2x3tan3x=
MathematicsLimitsTS EAMCETTS EAMCET 2021 (04 Aug Shift 2)
Options:
  • A -6
  • B 12
  • C 0
  • D -65
Solution:
2799 Upvotes Verified Answer
The correct answer is: 12

Given, limx01-cos2xxtan2x+2x3tan3x

=limx02sin2xxtan2x2x2x+2x3tan3x3x3x

=limx02sin2x2x2tan2x2x+tan3x3x

=limx0sinxx21tan2x2x+tan3x3x

=11+1

=12

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