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$$
\lim _{x \rightarrow 0}\left(\frac{4^x-1}{2^x-1}-\frac{\sqrt{4+3 x}-2}{x}\right)=
$$
Options:
\lim _{x \rightarrow 0}\left(\frac{4^x-1}{2^x-1}-\frac{\sqrt{4+3 x}-2}{x}\right)=
$$
Solution:
1764 Upvotes
Verified Answer
The correct answer is:
$\frac{5}{4}$
No solution. Refer to answer key.
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