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Question: Answered & Verified by Expert
limx→0(27+x)13-39-(27+x)23 equals 
MathematicsLimitsJEE MainJEE Main 2018 (16 Apr Online)
Options:
  • A -16
  • B  16
  • C  13
  • D -13
Solution:
1328 Upvotes Verified Answer
The correct answer is: -16
Given limit is limx→027+x13-3 9-27+x23   00 form

Applying L'Hospital's rule,

⇒limx→0 1327+x-23 -2327+x-13=27-23-227-13

=-122713 =-16.

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