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Question: Answered & Verified by Expert
$\lim _{x \rightarrow 0}\left(\frac{\sin a x}{\tan b x}\right)$ is equal to
MathematicsLimitsAP EAMCETAP EAMCET 2021 (25 Aug Shift 1)
Options:
  • A $a b$
  • B $\frac{a}{b}$
  • C $\frac{b}{a}$
  • D 1
Solution:
1852 Upvotes Verified Answer
The correct answer is: $\frac{a}{b}$
$\lim _{x \rightarrow 0}\left(\frac{\sin a x}{\tan b x}\right)$
$$
\lim _{x \rightarrow 0} a\left(\frac{\sin a x}{a x}\right) \times \lim _{x \rightarrow 0} \frac{1}{\left(\frac{\tan b x}{b x}\right) b}=a \times \frac{1}{b}=\frac{a}{b}
$$

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