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Question: Answered & Verified by Expert
$\lim _{x \rightarrow 0} x^2 \sin \frac{\pi}{x}$ is equal to
MathematicsLimitsTS EAMCETTS EAMCET 2005
Options:
  • A 1
  • B 0
  • C does not exist
  • D $\infty$
Solution:
1560 Upvotes Verified Answer
The correct answer is: 0
$\begin{aligned} & \lim _{x \rightarrow 0} x^2 \sin \left(\frac{\pi}{x}\right) \\ &=\lim _{x \rightarrow 0} \pi x \cdot \frac{\sin \frac{\pi}{x}}{\frac{\pi}{x}}=0(1)=0\end{aligned}$

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