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$\lim _{x \rightarrow 0}\left(\frac{a^x-b^x}{x}\right)=$
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The correct answer is:
$\log \left(\frac{a}{b}\right)$
$\begin{aligned} \lim _{x \rightarrow 0} \frac{a^x-b^x}{x} & =\lim _{x \rightarrow 0}\left(\frac{a^x-1}{x}\right)-\lim _{x \rightarrow 0}\left(\frac{b^x-1}{x}\right) \\ & =\log a-\log b=\log (a / b) .\end{aligned}$
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