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$\lim _{x \rightarrow 0} x^x=$
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Verified Answer
The correct answer is:
$1$
Let $y=x^x \Rightarrow \log y=x \log x$
$\lim _{y \rightarrow 0} \log y=\lim _{x \rightarrow 0} x \log x=0=\log 1 \Rightarrow \lim _{x \rightarrow 0} x^x=1$
$\lim _{y \rightarrow 0} \log y=\lim _{x \rightarrow 0} x \log x=0=\log 1 \Rightarrow \lim _{x \rightarrow 0} x^x=1$
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