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$\lim _{x \rightarrow 0} \frac{y^2}{x}=\ldots \ldots \ldots$ where $y^2=a x+b x^2+c x^3$
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The correct answer is:
a
$\lim _{x \rightarrow 0} \frac{a x+b x^2+c x^3}{x}=\lim _{x \rightarrow 0} \frac{a+b x+c x^2}{1}=a$
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