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$\lim _{x \rightarrow 1} \frac{x-1}{2 x^2-7 x+5}=$
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Verified Answer
The correct answer is:
$-1 / 3$
$\lim _{x \rightarrow 1} \frac{x-1}{(x-1)(2 x-5)}=-\frac{1}{3} .$
Aliter : Apply L-Hospital's rule.
So, \(\lim _{x \rightarrow 1} \frac{1}{4 x-7}=-\frac{1}{3} .\)
Aliter : Apply L-Hospital's rule.
So, \(\lim _{x \rightarrow 1} \frac{1}{4 x-7}=-\frac{1}{3} .\)
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