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$\lim _{x \rightarrow \infty}\left(1+\frac{2}{x}\right)^x=$
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The correct answer is:
$e^2$
$\left[\lim _{x \rightarrow \infty}\left(1+\frac{1}{x / 2}\right)^{x / 2}\right]^2=e^2$ as \(\lim _{x \rightarrow \infty}\left(1+\frac{1}{x}\right)^x=e\)
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