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Question: Answered & Verified by Expert
$\lim _{x \rightarrow \infty}\left(1+\frac{2}{x}\right)^x=$
MathematicsLimitsJEE Main
Options:
  • A $e$
  • B $\frac{1}{e}$
  • C $e^2$
  • D None of these
Solution:
2393 Upvotes Verified Answer
The correct answer is: $e^2$
$\left[\lim _{x \rightarrow \infty}\left(1+\frac{1}{x / 2}\right)^{x / 2}\right]^2=e^2$ as \(\lim _{x \rightarrow \infty}\left(1+\frac{1}{x}\right)^x=e\)

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