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$\lim _{x \rightarrow \infty} \frac{(2 x+1)^{40}(4 x-1)^5}{(2 x+3)^{45}}=$
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$32$
$\lim _{x \rightarrow \infty} \frac{\left(2+\frac{1}{x}\right)^{40}\left(4-\frac{1}{x}\right)^5}{\left(2+\frac{3}{x}\right)^{45}}=\frac{2^{40} \cdot 4^5}{2^{45}}=2^5=32$.
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