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Question: Answered & Verified by Expert
\(\lim _{x \rightarrow 0}(1+3 x)^{\frac{2}{x}}=\)
MathematicsLimitsAP EAMCETAP EAMCET 2020 (18 Sep Shift 1)
Options:
  • A 6
  • B \(e^6\)
  • C \(e^{-6}\)
  • D \(e^{\frac{1}{6}}\)
Solution:
2378 Upvotes Verified Answer
The correct answer is: \(e^6\)
\(\begin{aligned}
\operatorname{Lim}_{x \rightarrow 0}(1 & +3 x) \frac{2}{x}=\operatorname{Lim}_{x \rightarrow 0}\left((1+3 x)^{\frac{1}{3 x}}\right)^6 \\
=e^6 \quad & \left\{\because \operatorname{Lim}_{x \rightarrow 0}(1+a x)^{\frac{1}{a x}}=e,(a \neq 0)\right\}
\end{aligned}\)

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