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Question: Answered & Verified by Expert
\( \lim _{x \rightarrow 0}\left\{(1+x)^{\frac{2}{x}}\right\} \) (where \( \{.\} \) denotes the fractional part of \( x \) ) is equal to
MathematicsLimitsJEE Main
Options:
  • A \( e^{2}-7 \)
  • B \( e^{2}-8 \)
  • C \( e^{2}-6 \)
  • D None of these
Solution:
2712 Upvotes Verified Answer
The correct answer is: \( e^{2}-7 \)

We know, 1+x2/x=1+x2/x-1+x2/x

Also,   limx01+x2/x=e2

limx01+x2/x=limx01+x2/x-limx01+x2/x

=e2-e2=e2-7

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