lim x → α x − α s i n x − s i n α =, 0, 1, sin α, cos α

lim x → α 1 c o s x = cos α , (Apply L-Hospital's rule)

lim x → α x − α s i n x − s i n α =

Question: Answered & Verified by Expert

$\lim _{x \rightarrow \alpha} \frac{\sin x-\sin \alpha}{x-\alpha}=$

MathematicsLimitsJEE Main

Options:

Solution:

1973 Upvotes Verified Answer

The correct answer is: $\cos \alpha$

$\lim _{x \rightarrow \alpha} \frac{\cos x}{1}=\cos \alpha$, (Apply L-Hospital's rule)

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.