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List I describes four systems, each with two particles A and B in relative motion as shown in figure. List II gives possible magnitudes of their relative velocities (in m s-1) at time t=π3 s.

  List-I   List-II
(I)

A and B are moving on a horizontal circle of radius 1 m with uniform angular speed ω=1 rad s-1. The initial angular positions of A and B at time t=0 are θ=0 and θ=π2 respectively.

(P) 3+12
(II)

Projectiles A and B are fired (in the same vertical plane) at t=0 and t=0.1 s respectively, with the same speed v=5π2 m s-1 and at 45° from the horizontal plane. The initial separation between A and B is large enough so that they do not collide, g=10 m s-2.

(Q) 3-12
(III)

Two harmonic oscillators A and B moving in the x direction according to xA=x0sintt0 and xB=x0sintt0+π2 respectively, starting from t=0. Take x0=1 m,t0=1 s.

(R) 10
(IV)

Particle A is rotating in a horizontal circular path of radius 1 m on the xy plane, with constant angular speed ω=1 rad s-1. Particle B is moving up at a constant speed 3 m s-1 in the vertical direction as shown in the figure. (Ignore gravity.)

(S) 2
    (T) 25π2+1

Which one of the following options is correct?

PhysicsWork Power EnergyJEE AdvancedJEE Advanced 2022 (Paper 1)
Options:
  • A IR,IIT,IIIP,IVS
  • B IS,IIP,IIIQ,IVR
  • C IS,IIT,IIIP,IVR
  • D IT,IIP,IIIR,IVS
Solution:
1854 Upvotes Verified Answer
The correct answer is: IS,IIT,IIIP,IVR

(I)

Angular velocity of both the particles is same. Therefore, angle between them will remain 90°.

vrel=2ωR=2 m s-1

Hence, IS

(II)

The velocity of A at any time t can be written as

vAt=5π2cos45°i^+5π2×sin45°-g×tj^

=5π2i^+5π2-gtj^

Velocity of B at any time t

vBt=-5π2i^+5π2-gt-0.1j^

Relative velocity at time t will be,

vrel=5πi^-g×0.1j^

vrel=25π2+1 m s-1

Hence, IIT

(III) 

Relative position of A wrt B can be written as

x=xA-xB=x0sint-x0sint+π2

Using trigonometric relation

x=2x0sint-π4

Therefore,

vrel=dxdt=2x0cost-π4

at t=π3

vrel=2cosπ3-π4=2×3+122=3+12 m s-1

Hence, IIIP

(IV) 

The velocity of A is in xy plane and it is vA=ωr=1 m s-1 and the velocity of B is along z axis and vB=3 m s-1. Therefore,

vrel=32+12=10 m s-1

Hence, IVR

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