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$\int \log x d x=$
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Verified Answer
The correct answer is:
$x \log x-x+c$
$\int \log x d x=x \log x-\int x \cdot \frac{1}{x} d x+c=x \log x-x+c$
Note : Students should remember this question as a formula.
Note : Students should remember this question as a formula.
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