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Locus of the point of intersection of perpendicular tangents to the circle $x^{2}+y^{2}=16$ is
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The correct answer is:
$x^{2}+y^{2}=32$
We know that, if two perpendicular tangents to the circle $x^{2}+y^{2}=a^{2}$ meet at $P$, then the point
$P$ lies on a director circle. $\therefore$ Required locus is $x^{2}+y^{2}=32$
$P$ lies on a director circle. $\therefore$ Required locus is $x^{2}+y^{2}=32$
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