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Λ°m for NaCl, HCl and NaAc are 126.4, 425.9 and 91.0 S cm2 mol-1 respectively. Calculate Λ°m for HAc.
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The correct answer is:
390.5 S cm² mol⁻¹
Λ°m(HAc) = λ° (H+) + λ° (Ac)- = λ° (H+) + λ° (Cl-) + λ° (Ac-) + λ° (Na +) - λ° (Cl-) - λ° (Na+)= Λ°m(HCl) + Λ°m (NaAc) - Λ°m (NaCl)= (425.9 + 91.0 – 126.4 ) S cm2 mol -1= 390.5 S cm² mol⁻¹
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