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Question: Answered & Verified by Expert
M grams of steam at 100oC is mixed with 200g of ice at its melting point in a thermally insulated container. If it produces liquid water at 40oC [heat of vaporization of water is 540cal/g and heat of fusion of ice is 80cal/g ], the value of M is ________
PhysicsThermal Properties of MatterJEE MainJEE Main 2020 (07 Jan Shift 2)
Solution:
1316 Upvotes Verified Answer
The correct answer is: 40
MiceLf+Mice40-0Cw=MsteamLv+Msteam100-40Cw
20080+401=M540+601
200120=M600
M=40 gm

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