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Question: Answered & Verified by Expert
Match List I (equations) with List II (types of process) and select the correct OPTION.


ChemistryThermodynamics (C)NEETNEET 2010 (Mains)
Options:
  • A (a)
  • B (b)
  • C (c)
  • D (d)
Solution:
2035 Upvotes Verified Answer
The correct answer is: (c)
(A) When $K_p > Q$, the reaction goes in forward direction, ie, the reaction is spontaneous.
(B) Given, $\Delta G^{\circ} < R T \ln Q$, thus, $\Delta \mathrm{G}^{\circ}=+$ ve and hence, the reaction is nonspontaneous.
(C) At equilibrium, $\mathrm{K}_{\mathrm{p}}=\mathrm{Q}$
(D) $\mathrm{T} > \frac{\Delta \mathrm{H}}{\Delta \mathrm{S}}$ or $\mathrm{T} \Delta \mathrm{S} > \Delta \mathrm{H}$
This condition is true for spontaneous endothermic reactions (as $\Delta G \geq \Delta \mathrm{H}-\mathrm{T} \Delta \mathrm{S}$).

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