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Match List I with List II and select the correct answer using the codes given below the lists:


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The correct answer is:
(d)
From thermodynamics, $d G=V d P-S d T$
At constant $T, d T=0$ so that $\left(\frac{\delta G}{\delta P}\right)_T=V$
At constant $P, d P=0$ so that $\left(\frac{\delta G}{\delta T}\right)_P=-S$
$\mathrm{Also} \mu_{J T}=\left(\frac{\delta T}{\delta P}\right)_H$
At constant $T, d T=0$ so that $\left(\frac{\delta G}{\delta P}\right)_T=V$
At constant $P, d P=0$ so that $\left(\frac{\delta G}{\delta T}\right)_P=-S$
$\mathrm{Also} \mu_{J T}=\left(\frac{\delta T}{\delta P}\right)_H$
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