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Question: Answered & Verified by Expert
Match List I with List II
\(\begin{array}{|l|l|l|l|}
\hline & \text{List - I} & & \text{List - II} \\
& \text{(Compound/Species)} & & \text{(Shape/Geometry)} \\
\hline \text { A. } & \mathrm{SF}_4 & \text { I. } & \text { Tetrahedral } \\
\hline \text { B. } & \mathrm{BrF}_3 & \text { II. } & \text { Pyramidal } \\
\hline \text { C. } & \mathrm{BrO}_3^{-} & \text {III. } & \text { See saw } \\
\hline \text { D. } & \mathrm{NH}_4^{+}{ }^{+} \mathrm{KS} & \text { IV. } & \text { Bent T-Shape } \\
\hline
\end{array}\)
Choose the correct answer from the options given below:
ChemistryChemical Bonding and Molecular StructureJEE MainJEE Main 2024 (06 Apr Shift 1)
Options:
  • A A-II, B-III, C-I, D-IV
  • B A-II, B-IV, C-III, D-I
  • C A-III, B-IV, C-II, D-I
  • D A-III, B-II, C-IV, D-I
Solution:
1457 Upvotes Verified Answer
The correct answer is: A-III, B-IV, C-II, D-I

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