Match List I with List II List I List II A. Torque I. M L - 2 T - 2 B. Stress II. M L 2 T - 2 C. Pressure gradient III. M L - 1 T - 1 D. Coefficient of viscosity IV. M L - 1 T - 2 Choose the correct answer from the options given below :

Question

Match List I with List II List I List II A. Torque I. M L - 2 T - 2 B. Stress II. M L 2 T - 2 C. Pressure gradient III. M L - 1 T - 1 D. Coefficient of viscosity IV. M L - 1 T - 2 Choose the correct answer from the options given below :, A-II, B-I, C-IV, D-III, A-IV, B-II, C-III, D-I, A-II, B-IV, C-I, D-III, A-III, B-IV, C-I, D-II

MARKS App · Accepted Answer

The dimensions of the quantities are as follows. F = M L T - 2 r = L v = L T - 1 A = L 2 The dimensional form of stress is same as pressure. Torque = Force × distance = ML 2 T - 2 Stress = Force Area = M L - 1 T - 2 Pressure Gradient = d p d x = ML - 2 T - 2 η = F 6 π r v = M L T - 2 L · LT - 1 = ML - 1 T - 1

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	List I		List II
A.	Torque	I.	$M L^{- 2} T^{- 2}$
B.	Stress	II.	$M L^{2} T^{- 2}$
C.	Pressure gradient	III.	$M L^{- 1} T^{- 1}$
D.	Coefficient of viscosity	IV.	$M L^{- 1} T^{- 2}$