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Question: Answered & Verified by Expert

Match List I with List II.

List I List II
Reaction Reagents
(A) Hoffmann
Degradation
(I) Conc.KOH,Δ
(B) Clemmensen
reduction
(II) CHCl3,NaOH/H3O+
(C) Cannizzaro reaction (III) Br2,NaOH
(D) Reimer-Tiemann
reaction
(IV) Zn-Hg/HCl
ChemistryAldehydes and KetonesJEE MainJEE Main 2023 (29 Jan Shift 1)
Options:
  • A (A) - III, (B) - IV, (C) - II, (D) - I
  • B (A) - II, (B) - IV, (C) - I, (D) - III
  • C (A) - III, (B) - IV, (C) - I, (D) - II
  • D (A) - II, (B) - I, (C) - III, (D) - IV
Solution:
1217 Upvotes Verified Answer
The correct answer is: (A) - III, (B) - IV, (C) - I, (D) - II

(A) Hoffmann degradation reaction: Hoffmann developed a method for the preparation of primary amines by treating an amide with bromine in an aqueous or ethanolic solution of sodium hydroxide. 

       O             R-C-NH2 + Br2 + 4NaOH  R-NH2 + Na2CO3 + 2NaBr + 2H2O

(B) Clemmensen reduction reaction: The Clemmensen reduction is a reaction that is used to reduce aldehydes or ketones to alkanes using hydrochloric acid and zinc amalgam.

(C) Cannizzaro reaction: Aldehydes which do not have an α-hydrogen atom, undergo self-oxidation and reduction (disproportionation) reaction on heating with concentrated alkali.

(D) Reimer-Tiemann reaction: On treating phenol with chloroform in the presence of sodium hydroxide, a –CHO group is introduced at ortho position of benzene ring. This reaction is known as Reimer-Tiemann reaction.

So, the correct matching is given in the following table:

Reactions

Reagent used
(A) Hoffmann degradation Br2/NaOH
(B) Clemmensen reduction Zn-Hg/HCl
(C) Cannizzaro reaction conc.KOH/ KOH/
(D) Reimer-Tiemann reaction CHCl3,NaOH/H3O+

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