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Match List-I with List-II:
Choose the correct answer from the options given below :
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The correct answer is:
(a)-(iii), (b)-(iv), (c)-(ii), (d)-(i)
$\begin{array}{|c|c|c|c|}\hline \begin{array}{c}\text { Principle } \\ \text { QN }(n)\end{array} & \begin{array}{c}\text { Azimuthal } \\ \text { QN }(l)\end{array} & \begin{array}{c}\text { Possible } \\ \text { values } \\ (n-1)\end{array} & \text { Subshell } \\ \hline n=1 & 0 & & s \\ \hline n=2 & 0 & & s \\ & 1 & & p \\ \hline n=3 & 0 & & s \\ & 1 & & p \\ & 2 & & d \\ \hline n=4 & 0 & & s \\ & 1 & & p \\ & 2 & & d \\ & 3 & & f \\ \hline \end{array}$
So, for $n=2, l=1$, orbital is $2 p$ for $n=3, l=2$, orbital is $3 d$ for $n=3, l=0$, orbital is $3 \mathrm{~s}$ for $n=2, l=0$, orbital is $2 s$
So, for $n=2, l=1$, orbital is $2 p$ for $n=3, l=2$, orbital is $3 d$ for $n=3, l=0$, orbital is $3 \mathrm{~s}$ for $n=2, l=0$, orbital is $2 s$
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