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Question:
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Match the following and choose the correct code.
Codes
$\begin{array}{llll}A & B & C & D\end{array}$
Options:
Codes
$\begin{array}{llll}A & B & C & D\end{array}$
Solution:
1064 Upvotes
Verified Answer
The correct answer is:
$\begin{array}{llll}3 & 4 & 1 & 2\end{array}$
Wurtz reaction is a coupling reaction where two alkyl halides are reacted with sodium metal in dry ether to give higher alkane.
$2 R-\mathrm{Br} \xrightarrow{\mathrm{Na}} R-R+2 \mathrm{NaBr}$
In decarboxylation, a carboxyl group is removed and $\mathrm{CO}_2$ is released.
$R \mathrm{COO}^{-} \mathrm{Na}^{+} \xrightarrow[\mathrm{CaO}, \Delta]{\mathrm{NaOH}} R-\mathrm{H}$
Lindlar's catalyst has 3 components i.e. palladium-calcium carbonate, lead acetate and quinoline. Quinoline prevents complete hydrogenation of alkynes to alkane resulting in partial reduction.
Electrophilic addition reaction occurs between electrophile and a nucleophile, adding to double or triple bond.
$\mathrm{CH}_2=\mathrm{CH}_2 \xrightarrow[\mathrm{CCl}_4]{\mathrm{Br}_2} \mathrm{Br}-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{Br}$
So, correct match is
$(A-3),(B-4),(C-1),(D-2)$.
$2 R-\mathrm{Br} \xrightarrow{\mathrm{Na}} R-R+2 \mathrm{NaBr}$
In decarboxylation, a carboxyl group is removed and $\mathrm{CO}_2$ is released.
$R \mathrm{COO}^{-} \mathrm{Na}^{+} \xrightarrow[\mathrm{CaO}, \Delta]{\mathrm{NaOH}} R-\mathrm{H}$
Lindlar's catalyst has 3 components i.e. palladium-calcium carbonate, lead acetate and quinoline. Quinoline prevents complete hydrogenation of alkynes to alkane resulting in partial reduction.
Electrophilic addition reaction occurs between electrophile and a nucleophile, adding to double or triple bond.
$\mathrm{CH}_2=\mathrm{CH}_2 \xrightarrow[\mathrm{CCl}_4]{\mathrm{Br}_2} \mathrm{Br}-\mathrm{CH}_2-\mathrm{CH}_2 \mathrm{Br}$
So, correct match is
$(A-3),(B-4),(C-1),(D-2)$.
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