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Match the following
\begin{array}{llll}
& List I & & List II \\
& (Group 13 element) & & (metallic radius, pm) \\
A & \mathrm{Al} & I & 135 \\
\mathrm{~B} & \mathrm{Ga} & II & 143 \\
\mathrm{C} & In & III & 170 \\
\mathrm{D} & \mathrm{Tl} & IV & 167
\end{array}
The correct answer is
Options:
\begin{array}{llll}
& List I & & List II \\
& (Group 13 element) & & (metallic radius, pm) \\
A & \mathrm{Al} & I & 135 \\
\mathrm{~B} & \mathrm{Ga} & II & 143 \\
\mathrm{C} & In & III & 170 \\
\mathrm{D} & \mathrm{Tl} & IV & 167
\end{array}
The correct answer is
Solution:
2296 Upvotes
Verified Answer
The correct answer is:
A-II, B-I, C-IV, D-III
The atomic radii or metallic radii of elements increases down the group due to increasing shells with the exception of Gallium $(\mathrm{Ga})$ in the $13^{\text {th }}$ group.
This is due to the presence of d-subshell that offers poorer shielding of the outermost p-electrons.
Thus, the order of metallic radius will be:-
$$
\mathrm{Ga} < \mathrm{Al} < \mathrm{In} < \mathrm{Tl}
$$
This is due to the presence of d-subshell that offers poorer shielding of the outermost p-electrons.
Thus, the order of metallic radius will be:-
$$
\mathrm{Ga} < \mathrm{Al} < \mathrm{In} < \mathrm{Tl}
$$
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