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Match the following
List-I (Molecule) List - II (Shape)
A. $\mathrm{XeF}_4$ I. Square pyramid,
B. $\mathrm{ClF}_3$ II. Pentagonal bipyramidal
C. $\mathrm{BrF}_5$ III. Square planar
D. $\mathrm{IF}_7$ IV. Bent T-Shape
Options:
List-I (Molecule) List - II (Shape)
A. $\mathrm{XeF}_4$ I. Square pyramid,
B. $\mathrm{ClF}_3$ II. Pentagonal bipyramidal
C. $\mathrm{BrF}_5$ III. Square planar
D. $\mathrm{IF}_7$ IV. Bent T-Shape
Solution:
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Verified Answer
The correct answer is:
A-III; B-IV; C-I; D-II
$\mathrm{XeF}_4$ is square planar in shape due to four bond pairs and two lone pairs that form an octahedral geometry. $\mathrm{ClF}_3$ is Bent T-shaped due to three bond pairs and two lone pairs around the central $\mathrm{Cl}$ atom that together form a trigonal bipyramidal geometry with the two lone pairs occupying the equatorial positions.
$\mathrm{BrF}_5$ is square pyramidal in shape due to five bond pairs and one lone pair around $\mathrm{Br}$ with an octahedral geometry. $\mathrm{IF}_7$ is pentagonal bipyramidal due to seven bond pairs that a range themselves in this position to minimise the repulsion.

$\mathrm{BrF}_5$ is square pyramidal in shape due to five bond pairs and one lone pair around $\mathrm{Br}$ with an octahedral geometry. $\mathrm{IF}_7$ is pentagonal bipyramidal due to seven bond pairs that a range themselves in this position to minimise the repulsion.

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