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The correct answer is
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The correct answer is
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A - III, B - I, C - IV, D - II
Bakelite is a condensation polymer of phenol and formaldehyde.
Thus, $\mathrm{A} \rightarrow$ III.
Natural rubber is an addition polymer of - 2 -methyle- 1,3 -butadiene
Thus, $\mathrm{B} \rightarrow \mathrm{I}$.
Glyptal is a condensation polymer of phthalic acid and ethylene glycol.
Thus, $\mathrm{C} \rightarrow$ IV.
Nylon 2-Nylon 6 is a condensation polymer of glycine and aminocaproic acid.
Thus, D $\rightarrow$ II.
Thus, $\mathrm{A} \rightarrow$ III.
Natural rubber is an addition polymer of - 2 -methyle- 1,3 -butadiene
Thus, $\mathrm{B} \rightarrow \mathrm{I}$.
Glyptal is a condensation polymer of phthalic acid and ethylene glycol.
Thus, $\mathrm{C} \rightarrow$ IV.
Nylon 2-Nylon 6 is a condensation polymer of glycine and aminocaproic acid.
Thus, D $\rightarrow$ II.
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