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Question: Answered & Verified by Expert
Match the geometry (given in column A ) with the complexes (given in column B ) in:
  Geometry: A   Complex: B
I Octahedral (P) [Ni(CN)4]2-
II Square planar (Q) Ni(CO)4
III Tetrahedral (R) [Fe(CN)6]4-
ChemistryCoordination CompoundsNEET
Options:
  • A I-P,II-Q,III-R
  • B I-R,II-P,III-Q
  • C I-R,II-Q,III-P
  • D I-Q,II-P,III-R
Solution:
1169 Upvotes Verified Answer
The correct answer is: I-R,II-P,III-Q
In [Fe(CN)6]4-Fe is in +2 state with elctronic configuration 4so3d6 and CN- is strong ligand causes inward pairing, thus shows d2sp3 , Octahedral. Ni(CO)4 is sp3 tetrahedral and [Ni(CN)4]2- is dsp2 , square planar.

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