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Match the items of List - I with those of List - II
$\begin{array}{ll}
\text{List - I (Complex number)} & \text{List - II (Polar form)} \\
\text{(i)} \sqrt{3}-i & \text{(a)} 2 \operatorname{cis} \frac{\pi}{6} \\
\text{(ii)} \sqrt{3}+i & \text{(b)} 2 \operatorname{cis} \frac{5 \pi}{6} \\
\text{(iii)} -\sqrt{3}+i & \text{(c)} 2 \operatorname{cis}\left(\frac{-5 \pi}{6}\right) \\
\text{(iv)} -\sqrt{3}-i & \text{(d)} 2 \operatorname{cis}\left(-\frac{\pi}{6}\right) \\
& \text{(e)} 2 \operatorname{cis} \frac{9 \pi}{6} \\
\end{array}$
The correct matching is
Options:
$\begin{array}{ll}
\text{List - I (Complex number)} & \text{List - II (Polar form)} \\
\text{(i)} \sqrt{3}-i & \text{(a)} 2 \operatorname{cis} \frac{\pi}{6} \\
\text{(ii)} \sqrt{3}+i & \text{(b)} 2 \operatorname{cis} \frac{5 \pi}{6} \\
\text{(iii)} -\sqrt{3}+i & \text{(c)} 2 \operatorname{cis}\left(\frac{-5 \pi}{6}\right) \\
\text{(iv)} -\sqrt{3}-i & \text{(d)} 2 \operatorname{cis}\left(-\frac{\pi}{6}\right) \\
& \text{(e)} 2 \operatorname{cis} \frac{9 \pi}{6} \\
\end{array}$
The correct matching is
Solution:
1143 Upvotes
Verified Answer
The correct answer is:
$\begin{array}{cccc}
\text { (i) } & \text { (ii) } & \text { (iii) } & \text { (iv) } \\
\text { d } & \text { a } & \text { b } & \text { c } \\
\end{array}$
\text { (i) } & \text { (ii) } & \text { (iii) } & \text { (iv) } \\
\text { d } & \text { a } & \text { b } & \text { c } \\
\end{array}$
No solution. Refer to answer key.
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