Search any question & find its solution
Question:
Answered & Verified by Expert
Solution:
1037 Upvotes
Verified Answer
The correct answer is:
1
1
$$
\operatorname{Lim}_{x \rightarrow 0} \frac{\sqrt{1-\cos 2 x}}{\sqrt{2} x} \Rightarrow \operatorname{Lim}_{x \rightarrow 0} \frac{\sqrt{1-\left(1-2 \sin ^2 x\right)}}{\sqrt{2} x} ; \operatorname{Lim}_{x \rightarrow 0} \frac{\sqrt{2 \sin ^2 x}}{\sqrt{2} x} \Rightarrow \operatorname{Lim}_{x \rightarrow 0} \frac{|\sin x|}{x}
$$
the function does not exist or $\mathrm{LHS} \neq \mathrm{RHS}$
\operatorname{Lim}_{x \rightarrow 0} \frac{\sqrt{1-\cos 2 x}}{\sqrt{2} x} \Rightarrow \operatorname{Lim}_{x \rightarrow 0} \frac{\sqrt{1-\left(1-2 \sin ^2 x\right)}}{\sqrt{2} x} ; \operatorname{Lim}_{x \rightarrow 0} \frac{\sqrt{2 \sin ^2 x}}{\sqrt{2} x} \Rightarrow \operatorname{Lim}_{x \rightarrow 0} \frac{|\sin x|}{x}
$$
the function does not exist or $\mathrm{LHS} \neq \mathrm{RHS}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.