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Question: Answered & Verified by Expert
\( \mathrm{RCOOH}+\mathrm{NaHCO}_{3} \rightarrow \mathrm{RCOONa}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \) The above reaction is showing the property of carboxylic acid.
ChemistryCarboxylic Acid DerivativesJEE Main
Options:
  • A acidic
  • B basic
  • C oxidizing
  • D reducing
Solution:
1496 Upvotes Verified Answer
The correct answer is: acidic

RCOOH+NaHCO3RCOONa+H2O+CO2

In the reaction, it can be clearly seen that carboxylic group gives proton which indicates its acidic character and sodium bicarbonate is taking proton, so it is behaving as base.

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