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\( \mathrm{RCOOH}+\mathrm{NaHCO}_{3} \rightarrow \mathrm{RCOONa}+\mathrm{H}_{2} \mathrm{O}+\mathrm{CO}_{2} \) The above reaction is showing the property of carboxylic acid.
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The correct answer is:
acidic
In the reaction, it can be clearly seen that carboxylic group gives proton which indicates its acidic character and sodium bicarbonate is taking proton, so it is behaving as base.
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