$\mathrm{SF}_6$ is a kinetically inert substance because

Question

$\mathrm{SF}_6$ is a kinetically inert substance because, fluorine is highly electronegative, it is sterically protected, greater difference in electronegativities of $\mathrm{S}$ and $\mathrm{F}$, larger size of S-atom

MARKS App · Accepted Answer

In $\mathrm{SF}_6$, sulphur is $s p^3 d^2$ hybridised. Both geometry and shape of the molecule is octahedral. $\mathrm{SF}_6$ is also a non-polar molecule (dipole moment, $\mu=0$ ), because if $a^{-}$and sterically protected perfectly symmetrical molecule. So, $\mathrm{SF}_6$ is also kinetically inert.

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