Molality ( $\mathrm{m}$ ) of $3 \mathrm{M}$ aqueous solution of $\mathrm{NaCl}$ is : (Given : Density of solution $=1.25 \mathrm{~g} \mathrm{~mL}^{-1}$, Molar mass in $\mathrm{g} \mathrm{mol}^{-1}: \mathrm{Na}-23, \mathrm{Cl}-35.5$)

Question

Molality ( $\mathrm{m}$ ) of $3 \mathrm{M}$ aqueous solution of $\mathrm{NaCl}$ is : (Given : Density of solution $=1.25 \mathrm{~g} \mathrm{~mL}^{-1}$, Molar mass in $\mathrm{g} \mathrm{mol}^{-1}: \mathrm{Na}-23, \mathrm{Cl}-35.5$), $1.9 \mathrm{~m}$, $3.85 \mathrm{~m}$, $2.79 \mathrm{~m}$, $2.90 \mathrm{~m}$

MARKS App · Accepted Answer

3 moles are present in 1 litre solution molality = 1.25 × 1000 − [ 3 × 58.5 ] 3 × 1000 ​ = 2.79 m

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