Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
Molar enthalpy change for vapourisation of $1.0 \mathrm{~mol}$ of water at $1.0 \mathrm{bar}$ and $100^{\circ} \mathrm{C}$ is $41.0 \mathrm{~kJ} \mathrm{~mol}^{-1}$. If water vapour is assumed to be an ideal gas, the internal energy change for $1.0 \mathrm{~g}$ of water in $\mathrm{kJ}$ is
ChemistryThermodynamics (C)AP EAMCETAP EAMCET 2017 (25 Apr Shift 2)
Options:
  • A $1.053$
  • B $4.212$
  • C $3.159$
  • D $2.106$
Solution:
1163 Upvotes Verified Answer
The correct answer is: $2.106$
No solution. Refer to answer key.

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.