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Molar volume is the volume occupied by 1 mole of any ideal gas at standard temperature and pressure (STP) which are 1 atmospheric pressure and $0^{\circ} \mathrm{C}$. Show that it is $22.4$ litres.
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For one mole of an ideal gas, $P V=R T$ $\therefore V=\frac{R T}{P}$ [Where, $R=8.31 \mathrm{~J} \mathrm{~mol}^{-1} \mathrm{~K}^{-1}$, $T=273 \mathrm{~K}, P=1$ atmosphere $\left.=1.013 \times 10^5 \mathrm{Nm}^{-2}\right]$ $=\frac{8.31 \times 273}{1.013 \times 10^5}=0.0224 \mathrm{~m}^3=22.4$ litres.
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