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Molarity of a given orthophosphoric acid solution is $3 \mathrm{M}$. It's normality is
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The correct answer is:
$9 \mathrm{~N}$
For orthoplwosphoric acid solution,
Molarity $=3 \mathrm{M}, \mathrm{s}$-factor $=3$
$\therefore \quad$ Nomnality $=n-$ factor $\times$ molarity
$=3 \times 3$
$=9 \mathrm{~N}$
Molarity $=3 \mathrm{M}, \mathrm{s}$-factor $=3$
$\therefore \quad$ Nomnality $=n-$ factor $\times$ molarity
$=3 \times 3$
$=9 \mathrm{~N}$
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