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Mutual inductance $M$ between two concentric coils of radii $1 \mathrm{~m}$ and $2 \mathrm{~m}$ is
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1658 Upvotes
Verified Answer
The correct answer is:
$\frac{\mu_0 \pi}{4}$
Here, $r_1=1 \mathrm{~m}, r_2=2 \mathrm{~m}$
$$
\text { Mutual inductance, } \begin{aligned}
M & =\frac{\mu_0 \pi r_1^2}{2 r_2} \\
& =\frac{\mu_0 \pi \times 1}{2 \times 2}=\frac{\mu_0 \pi}{4}
\end{aligned}
$$
$$
\text { Mutual inductance, } \begin{aligned}
M & =\frac{\mu_0 \pi r_1^2}{2 r_2} \\
& =\frac{\mu_0 \pi \times 1}{2 \times 2}=\frac{\mu_0 \pi}{4}
\end{aligned}
$$
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