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Question: Answered & Verified by Expert
\(N_1\) atoms of a radioactive element emit \(N_2\) beta particles per second. The decay constant of the element is (in s \({ }^{-1}\) )
PhysicsNuclear PhysicsAIIMSAIIMS 2008
Options:
  • A \(N_1 / N_2\)
  • B \(N_2 / N_1\)
  • C \(N_1(\ln 2)\)
  • D \(N_2(\ln 2)\)
Solution:
1668 Upvotes Verified Answer
The correct answer is: \(N_2 / N_1\)
$-\frac{d N}{d t}=\lambda N \Rightarrow N_2=\lambda N_1$

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