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$\mathrm{NaCl}$ has face centred structure with edge length equal to $361 \mathrm{pm}$. The radius is
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Verified Answer
The correct answer is:
$127.6 \mathrm{pm}$
For fcc lattice,
$\begin{gathered}
a \sqrt{2}=4 r \\
\therefore r=\frac{\sqrt{2}}{4} a \Rightarrow r=\frac{1.414 \times 361}{4} \Rightarrow r=127.6 \mathrm{pm}
\end{gathered}$
$\begin{gathered}
a \sqrt{2}=4 r \\
\therefore r=\frac{\sqrt{2}}{4} a \Rightarrow r=\frac{1.414 \times 361}{4} \Rightarrow r=127.6 \mathrm{pm}
\end{gathered}$
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